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    A 100 Ω resistance and a capacitor of 100 Ω reactance are connected in series across a 220 V source. When the capacitor is 50% charged, the peak value of the displacement current is

  • 11√ 2A
  • 2.2 A
  • 11 A
  • 4.4 A
  • Explanation:

    z= √R2+X2C=√(100)2+(100)2 = 100√2

    imax = vmax/2 = 220√2/100√ = 2.2