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    A tank has two inlets : P and Q. P alone takes 6 hours and Q alone takes 8 hours to fill the empty tank completely when there is no leakage. A leakage was caused which would empty the full tank completely in ‘X’ hours when no inlet is opened. Now, when only inlet P was opened, it took 15 hours to fill the empty tank completely. How much time will Q alone take to fill the empty tank completely ? (in hours)

  • 40 hours
  • 36 hours
  • 30 hours
  • 42 hours
  • 38 hours
  • Explanation:

    When taps P and X are opened,

    1/6-1/x=1/15

    1/x=1/6-1/15=15-6/15×6

    1/x=9/15×6

    X=10

    ∴ Required time = 40 hours