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    Two cars P and Q start from a point at the same time in a straight line and their positions are represented by xp(t) = at + bt2 and xQ (t) = ft – t2 . At what time do the cars have the same velocity

  • f – a /2(1+ b)
  • a – f /1 + b
  • a + f / 2(b – 1)
  • a + f / 2(1+ b)
  • Explanation:

    Vp=VQ

    a + 2bt = f – 2t = t = f-a/2(b+1)