Electrons of mass m with de-Broglie wavelength λ fall on the target in an X-ray tube. The cutoff wavelength (λ0) of the emitted X-ray is :

  • λ0 = λ
  • λ0= 2mcλ2/h
  • λ0=2h/mc
  • λ0=2m2c2λ3/h2
  • Explanation:

Electrons of mass m with de-Broglie wavelength λ fall on the target in an X-ray tube. Th
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