A Particle of unit mass undergoes one-dimensional
    motion such that its velocity varies according to
    v(x) = βx–2n
    where b and n are constants and x is the position
    of the particle. The acceleraion of the particle as
    a function of x, is given by :

  • –2nβ2x–4n–1
  • –2β2xx–2n–1
  • –2nβ2e–4n+1
  • –2nβ2x–2n–1
  • Explanation:

A Particle of unit mass undergoes one-dimensionalmotion such that its velocity varies according tov(
Home Ask Questions Study Current Affairs Previous Papers Kerala PSCIBPSUPSCRBITNPSCMPSCSSCCBSEUnited StatesModel Tests News More Answers Coaching Centres Careers Downloads Colleges