SBI SO (IT officer) Recruitment Examination Solved Question Paper - January 2016

  • Question 8 :
  • Statements :  Z≤H=N≤C≥M>S; G=K≥ C

    Conclusions : I. K>H

                       II. H=K

  • If either conclusion I or II is true
  • If neither conclusions I nor II is true
  • If both conclusions I and II are true
  • If only conclusion I is true
  • If only conclusion II is true
  • Explanation:

    Statements :  Z≤H=N≤C≥M>S

                        G=K≥ C

                        Z≤H=N≤C<k

                        G=K>C>M>S

    Conclusions : I. K>H → True

                       II. H=K → False

  • Question 9 :
  • Statements :  Z≤H=N≤C≥M>S; G=K≥ C

    Conclusions : I. Z≤ C

                       II. G>S

  • If either conclusion I or II is true
  • If neither conclusions I nor II is true
  • If both conclusions I and II are true
  • If only conclusion I is true
  • If only conclusion II is true
  • Explanation:

    Statements :  Z≤H=N≤C≥M>S

                        G=K≥ C

                        Z≤H=N≤C<k

                        G=K>C>M>S

    Conclusions : I. Z≤C → True

                       II. G>S → True

  • Question 35 :
  • Which of the following statements regarding Q is true

  • Only two persons live above Q’s floor.
  • Q lives on the topmost floor.
  • Q lives on an even numbered floor.
  • Only one person lives between Q and U.
  • None of these
  • Explanation:

    Floor Friend
    8 T
    7 P
    6 V
    5 Q
    4 S
    3 U
    2 W
    1 R

  • Question 51 :
  • I.  x2+5x+6=0

    II. 2y2+7y+6=0

  • If x≥y
  • y≤x
  • If x > y
  • If x
  • If relationship between x y and cannot be established
  • Explanation:

    I.x2+5x+6=0

    x2+3x+2x+6=0

    x(x+3)+2(x+3)=0

    (x+2)(x+3)=0

    x=-2, -3

    II. 2y2+7y+6 = 0

    2y2+4y+3y+6=0

    2y(y+2)+3(y+2)=0

    (y+2)(2y+3)=0

    y=-2, -3/2

  • Question 52 :
  • I. x2-13x+40=0

    II. y2-11y+28=0

  • If x≥y
  • If x≤y
  • If x > y
  • If x
  • If relationship between x y and cannot be established
  • Explanation:

    I. x2-13x+40=0

    x2-5x-8x+40=0

    x(x-5)-8(x-5)=0

    (x-5)(x-8)=0

    x=5,8

    II. y2-11y+28=0

    y2-7y-4y+28=0

    y(y-7)-4(y-7)=0

    (y-4)(y-7)=0

    y=4, 7

    ∴ x>y

  • Question 53 :
  • I. x2-10x+24=0

    II. 3y2-19y+28=0

  • If x≥y
  • If x≤y
  • If x > y
  • If x
  • If relationship between x and y cannot be established
  • Explanation:

    I. x2-10x+24=0

    x2-6x-4x+24=0

    x(x-6)-4(x-6)=0

    (x-4)(x-6)=0

    x=4, 6

    II. 3y2-19y+28=0

    3y2-12y-7y+28=0

    3y(y-4)-7(y-4)=0

    (y-4)(3y-7)=0

    y=4, 7/3

    ∴ x≥y

     

  • Question 54 :
  • I. 14x2-13x+3=0

    II. 99y2-62y+8=0

  • If x≥y
  • If x≤y
  • If x > y
  • If x
  • If relationship between x and y cannot be established
  • Explanation:

    I. 14x2-13x+3=0

    14x2-7x-6x+3=0

    7x(2x-1)-3(2x-1)=0

    (7x-3)(2x-1)=0

    x=3/7,1/2

    II. 99y2-62y+8=0

    99y2-44y-18y+8=0

    11y(9y-4)-2(9y-4)=0

    (9y-4)(11y-2)=0

    y=4/9,2/11

    ∴ Relationship between x and y cannot be established.

     

  • Question 55 :
  • I. 2x2-15x+28=0

    II. 2y2-21y+54=0

  • If x≥y
  • If x≤y
  • If x > y
  • If x
  • If relationship between x and y cannot be established.
  • Explanation:

    I. 2x2-15x+28=0

    2x2-8x-7x+28=0

    2x(x-4)-7(x-4)=0

    (x-4)(2x-7)=0

    x=4, 7/2

    II. 2y2-21y+54=0

    2y2-12y-9y+54=0

    2y(y-6)-9(y-6)=0

    (y-6)(2y-9)=0

    y=6, 9/2

    x<y

  • Question 58 :
  • 1, 2,6 ,21, ? ,445

  • 150
  • 185
  • 84
  • 292
  • 88
  • Explanation:

    1(×1+1)2(×2+2)6(×3+3)21(×4+4)88(×5+5)445

  • Question 60 :
  • 1.5, 2.5, 7, 24, 100

  • 345
  • 460
  • 525
  • 380
  • 505
  • Explanation:

    1.5(×1+1)2.5(×2+2)7(×3+3)24(×4+4)100(×5+5)505

  • Question 66 :
  • (8)0.75×(4096)0.25÷(64)-1=(8)?

  • 2.25
  • 3.0
  • 3.25
  • 3.50
  • 3.75
  • Explanation:

    (8)0.75×(4096)0.25÷(64)-1=(8)?

    (8)0.75×(84)0.25/(8)-2=(8)?

    80.75×81/8-2=(8)?

    (8)1.75+2=(8)?

    ?=1.75+2

    ?=3.75

  • Question 67 :
  • 3√17.576×15=?

  • 36
  • 39
  • 42
  • 45
  • 48
  • Explanation:

    3√17.576×15=?

    3√17.576/1000×15=?

    26/10×15=?

    ?=39

  • Question 68 :
  • 4.8% of 550-3.2% of 750 =?

  • 5.4
  • 4.8
  • 4.2
  • 3.6
  • 2.4
  • Explanation:

    4.8% of 550-3.2% of 750 =?

    4.8/100×550-3.2/100×750=?

    26.4-24=?

    ?=2.4

  • Question 69 :
  • √?+416 =(60% of 920) -110

  • 576
  • 676
  • 784
  • 1024
  • 1156
  • Explanation:

    √?+416 =(60% of 920) -110

    √?+416 =(60/100×920) -110

    √?+416=442

    √?=26

    ?=(26)2=676

  • Question 70 :
  • 63.5% of 8924.19+22% of 5324.42=?

  • 6278
  • 6128
  • 6228
  • 5624
  • 6838
  • Explanation:

    63.5% of 8924.19+22% of 5324.42=?

    63.5/100×8924+22/100×5324=?

    5666.74+1171.28=?

    ?=6838.02

    ?=6838

  • Question 78 :
  • The number of male Associate Professors in University A is what percent of the number of female Associate Professors in the same university

  • 25%
  • 15%
  • 22%
  • 28%
  • 26%
  • Explanation:

    University

    Total 

    number of 

    faculty

    members

    (male &

    female)

    Number of

    associate 

    professors

    (male &

    female)

    Number of

    professors 

    (male &

    female)

    Total 

    Number of

    female

    members

    Number of

    female

    Associate

    Professors

    Number of

    female

    Professors

    A 100

    100×65/100

    =65

    100-65

    =35

    72 52

    72-52

    =20

    B 80

    80×55/100

    =44

    80-44

    =36

    56 30

    56-30

    =26

    C 55

    55×60/100

    =33

    55-33

    =22

    40 24

    40-24

    =16

    D 90

    90×70/100

    =63

    90-63

    =27

    72 48

    72-48

    =24

    Number of female associate professors = 52

    Number of male associate professors = 65-52=13

    ∴ Required percentage = 13/52×100

    =25%

  • Question 79 :
  • What is the average number of Associate Professors in Universities C and D together

  • 46
  • 48
  • 52
  • 50
  • 54
  • Explanation:

    University

    Total 

    number of 

    faculty

    members

    (male &

    female)

    Number of

    associate 

    professors

    (male &

    female)

    Number of

    professors 

    (male &

    female)

    Total 

    Number of

    female

    members

    Number of

    female

    Associate

    Professors

    Number of

    female

    Professors

    A 100

    100×65/100

    =65

    100-65

    =35

    72 52

    72-52

    =20

    B 80

    80×55/100

    =44

    80-44

    =36

    56 30

    56-30

    =26

    C 55

    55×60/100

    =33

    55-33

    =22

    40 24

    40-24

    =16

    D 90

    90×70/100

    =63

    90-63

    =27

    72 48

    72-48

    =24

     

    Required average = 33+63/2

    =96/2=48

  • Question 81 :
  • What is the respective ratio between the number of female professors in University B and that in University D

  • 13:12
  • 17:12
  • 15:11
  • 13:11
  • 17:11
  • Explanation:

    University

    Total 

    number of 

    faculty

    members

    (male &

    female)

    Number of

    associate 

    professors

    (male &

    female)

    Number of

    professors 

    (male &

    female)

    Total 

    Number of

    female

    members

    Number of

    female

    Associate

    Professors

    Number of

    female

    Professors

    A 100

    100×65/100

    =65

    100-65

    =35

    72 52

    72-52

    =20

    B 80

    80×55/100

    =44

    80-44

    =36

    56 30

    56-30

    =26

    C 55

    55×60/100

    =33

    55-33

    =22

    40 24

    40-24

    =16

    D 90

    90×70/100

    =63

    90-63

    =27

    72 48

    72-48

    =24

    Required ratio = 26/24= 13:12

  • Question 82 :
  • What percentage of the total number of faculty members in Universities A and B together are male Associate Professors

  • 12%
  • 14.5%
  • 15%
  • 13%
  • 16.5%
  • Explanation:

    University

    Total 

    number of 

    faculty

    members

    (male &

    female)

    Number of

    associate 

    professors

    (male &

    female)

    Number of

    professors 

    (male &

    female)

    Total 

    Number of

    female

    members

    Number of

    female

    Associate

    Professors

    Number of

    female

    Professors

    A 100

    100×65/100

    =65

    100-65

    =35

    72 52

    72-52

    =20

    B 80

    80×55/100

    =44

    80-44

    =36

    56 30

    56-30

    =26

    C 55

    55×60/100

    =33

    55-33

    =22

    40 24

    40-24

    =16

    D 90

    90×70/100

    =63

    90-63

    =27

    72 48

    72-48

    =24

    Number of male associate professors in university A

    = 65-52=13

    Number of male associate professors in university B

    =44-30=14

    Total faculty members in universities A and B

    = 100+80=180

    ∴ Required percentage

    =(13+14)/180×100

    =27/180×100

    =90/6=15%

  • Question 83 :
  • What is the difference between the total number of male faculty members in Universities B and D together and the total number of female faculty members in Universities A and C together

  • 60
  • 69
  • 75
  • 72
  • 70
  • Explanation:

    University

    Total 

    number of 

    faculty

    members

    (male &

    female)

    Number of

    associate 

    professors

    (male &

    female)

    Number of

    professors 

    (male &

    female)

    Total 

    Number of

    female

    members

    Number of

    female

    Associate

    Professors

    Number of

    female

    Professors

    A 100

    100×65/100

    =65

    100-65

    =35

    72 52

    72-52

    =20

    B 80

    80×55/100

    =44

    80-44

    =36

    56 30

    56-30

    =26

    C 55

    55×60/100

    =33

    55-33

    =22

    40 24

    40-24

    =16

    D 90

    90×70/100

    =63

    90-63

    =27

    72 48

    72-48

    =24

    Number of male faculty members in university B

    = 80-56=24

    Number of male faculty members in university D

    = 90-72=18

    Total number of male faculty members in B and D

    =24+18=42

    Total number of female faculty members in A and C

    = 72+40=112

    ∴ Required difference = 112-42=70

     

  • Question 101 :
  • Which of the following can be inferred from the passage

  • Indonesia’s new government is adopt at communications about and implementing schemes.
  • Indonesia has too many unnecessary regulatory procedures and systems.
  • Indonesian economy is heavily dependent on exports of goods like cosmetics.
  • The current government has no intention of truly reforming Indonesia.
  • None of the given options can be inferred from the passage.
  • Question 106 :
  • Which of the following is the central idea of the passage

  • Indonesia needs more meaningful and developing reforms to boost economic growth.
  • Indonesia’s present government is not doing enough and should be voted out of power.
  • Indonesia is headed for a financial crash and foreign investors are pulling out quickly.
  • Indonesia’s reforms are too radical in nature and must destabilize its economy.
  • Other than those given as options
  • Question 107 :
  • What do the statistics cited about Indonesia’s economy reveal

  • Indonesia’s economy was not affected by the financial crisis of 2008.
  • The measures taken by Indonesia’s new government have ensured economic recovery.
  • The Indonesian government has not revealed the true extent of its economic recession.
  • Indonesia’s economy is not flourishing at present outside the government’s efforts.
  • Other than those given as options.
  • Question 109 :
  • Which of the following describes Indonesia’s labour market at present

  • Its labour force is not skilled and foreign workers are much in demand.
  • It will provide employment to millions of workers in the mining industry.
  • It provides the right of local at the cost of hiring foreign workers.
  • It has implemented an ambitious programme to skill Indonesian workers.
  • Not clearly mentioned in the passage.
  • Question 111 :
  • QST#111.

  • elevate
  • mitigate
  • amplify
  • cure
  • relieve
  • Question 112 :
  • QST # 112

  • Because
  • Thus
  • Yet
  • Till
  • Untill
  • Question 113 :
  • QST # 113

  • almost
  • scanty
  • popularly
  • just
  • barely
  • Question 114 :
  • QST # 114

  • reaching
  • beyond
  • arriving
  • joining
  • coming
  • Question 115 :
  • QST # 115

  • stay
  • drive
  • curl
  • constrain
  • migrate
  • Question 116 :
  • QST # 116

  • compensate
  • amount
  • cost
  • accrue
  • violent
  • Question 117 :
  • QST # 117

  • alarming
  • distressed
  • countering
  • delightful
  • shoddy
  • Question 118 :
  • QST # 118

  • approve
  • bare
  • harm
  • sustain
  • survive
  • Question 119 :
  • QST # 119

  • leading
  • causing
  • appealing
  • advancing
  • bulging
  • Question 120 :
  • QST # 120

  • frequent
  • number
  • sum
  • numerical
  • representation
  • Question 125 :
  • Which of the following is true of three-tier data worehouses

  • Once created, the data marts will directly receive their new data from the operational databases.
  • The data mart combines all the tables of the data warehouse.
  • The data marts are different groups of tables in the data warehouse.
  • Once created, the data marts will keep on being updated from the data warehouse at periodic times.
  • A data mart becomes a data warehouse when it reaches a critical size.
  • Question 130 :
  • To define what columns should be displayed in an SQL, SELECT statement ………..

  • use USING to name the source table(s)
  • use SELECT to name the source table(s) and list the columns to be shown after USING.
  • use USING to name the source table(s) and list the columns to be shown after SELECT.
  • use FROM to name the source table(s) and list the columns to be shown after SELECT.
  • use USING to name the source table(s) and list the columns to be shown after WHERE.
  • Question 132 :
  • Which of the following is a CASE SQL statement

  • A way to establish a data definition in SQL.
  • A way to establish an IF-THEN-ELSE in SQL.
  • Establish a loop in SQL or establish an IF-THEN-ELSE in SQL.
  • A way to establish a loop in SQL.
  • A way to establish a data definition in SQL or establish a loop in SQL.
  • Question 138 :
  • What is the main purpose of NCS software

  • To prevent viruses from entering a network
  • To ensure all users know how to use Windows
  • To prevent worms from entering a network
  • To control and coordinate activities and provide security in a network
  • To monitor the router settings
  • Question 144 :
  • Which of the following statement is false

  • Pointers are very useful.
  • Pointers store the next data element of a list
  • Data elements in linked lists need not be stored in adjacent space in memory
  • Linked lists are collection of the nodes that contain information part and next pointer.
  • Arrays are dense lists and static data structure.
  • Question 147 :
  •  In the concept of object orientation,…………..

  • Users change properties and cell functions
  • Designers can only call functions
  • Designers can only call calculations
  • Users change properties with their input devices
  • Designers convert binary data into object functions
  • Question 150 :
  •  Data mining is used to aid in……

  • analyzing current decisions made by managers
  • Operational management
  • retrieving archival data
  • analyzing past decisions made by managers
  • detecting patterns in operational data
  • Question 155 :
  • What is a scripting language

  • A powerful type of programming language
  • A programming language for creating websites
  • A more complex programming language
  • A programming language for writing operating systems
  • A programming language used within another application or domain
  • Question 162 :
  • Which of the following are true of Enterprise Systems

  • They include servers, databases and networks
  • They require specialized computer hardware
  • They are limited to access within the physical building
  • They require special locations
  • They require specialized computer software
SBI SO (IT officer) Recruitment Examination Solved Question Paper - January 2016
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