There are two bags – A and B, Bag A contain 6 red balls and 10 green balls and Bag B contains 4 red balls and 6 green balls. One bag is selected at random. From the selected bag one ball is drawn at random. What is the probability that the ball drawn is red
Probability of getting 1 red ball from bag A
=6C1/16C1=6/16=3/8
Probability of getting 1 red ball from bag B
=4C1/10C1=4/10=2/5
∴ Required probability = 1/2[3/8+4/10]
1/2[31/40]
=31/80
Directions (next five questions) : In these questions, two equations numbered I and II are given. You have to solve both the equations and
Give answer :
I. 2x2-15x+28=0
II. 2y2-21y+54=0
I. 14x2-13x+3=0
II. 99y2-62y+8=0
I. x2-10x+24=0
II. 3y2-19y+28=0
I. x2-13x+40=0
II. y2-11y+28=0
I. x2+5x+6=0
II. 2y2+7y+6=0
