The solution for L (t2 e2t) is
The number of real roots of the equation
(x-1)2+(x-2)2+(x-3)2 = 0 is
Order & degree of differential equation d2y/dx2={y+[dy/dx]2}1/4 are
Solution of differential equation xdy-ydx=0 represents
The auxiliary equation of (aD2+bD+c) = 0 is having two real & distinct roots m1 & m2 then the general solution is
The PDE ∂2u/∂x2+∂2u/∂y2 = f(x,y) is called as