Aptitude Questions & Answers (Compiled from previous question papers)

Quantitative Aptitude is an inevitable section for the competitive exams of India.It analyses the mathematical skills of a student.Knowledge of basic skills in mathematics is evident for competitive exams,though it is not mandatory,questions for exams like CDS,UPSC(CSAT),PSC are of basic tenth standard level.

Quantitative Aptitude questions are asked from chapters like Boats and Streams,Time and Work Compound Interestetc .In this section we have also given steps and diagrams to each question ,making it easier for the students to understand.Our this section of Quantitative Aptitude are sorted according to different chapters made easier for students to go through questions chapter wise.We also update newly modeled questions to update students on change of pattern.Look at the question below which are given chapter wise and which is helpful for aspirants of Banking(IBPS),SSC,PSC,CDS and UPSC(CSAT).

Latest Aptitude Questions & Answers

The compound interest earned on a sum in 3 years at 15% per annum compounded annually is INR 6500. 52. What is the sum
INR 12480/-
INR 10500/-
INR 14800/-
INR 13620/-
None of these
Explanation:

Let the sum = INR P

According to question,

6500.52 = P [(1+15/100)³-1]

6500.52/0.520875 = P

The area of circle is seven times the numerical value of its circumference. What is the circumference of the circle
616 units
132 units
88 units
Cannot be determined
None of these
Explanation:

Let the radius of circle =r unit

According to question,

πr²=7×2πr

r = 14 unit

Circumference of the circle = 2 × 22/7 × 14

= 88 units

Directions (next five questions) : What will come at the place of question mark (?) in the following number series.

3 4 16 75 364 ?
783
828
1293
1945
None of these

4000 800 ? 80 40 8
140
100
400
160
200

4 10 33 136 ? 4116
822
534
685
745
548
Explanation:

4(×2+2)10(×3+3)33(×4+4)136(×5+5)685(×6+6)4116

10 18 34 ? 130 258
32
60
66
68
None of these
Explanation:

3 1731 ? 3243 3459 3523
2371
2731
3731
3127
None of these
Explanation:

3((+12)³)1731((+10)³)2731((+8)³)3243((+6)³)3523((+4)³)3523

Directions (next five questions) : In each of the following questions, two equations are given. Solve these equations and

I. x=√625

II. y=√676
If x ≥ y
If x > y
if x ≤ y
If x < y
If x = y or no relation can be established between x and y.
Explanation:

I. x=√625 = ±25

II. y=√676 = ±26

I. 2x+3y=14

II. 4x+2y=16
If x ≥ y
If x > y
if x ≤ y
If x < y
If x = y or no relation can be established between x and y.
Explanation:

I. 2x+3y=14

II. 4x+2y=16

Solving I and II, we get,

x= 2.5, y=3

x<y

I. x²+20 = 9x

II. y²+42=13y
If x ≥ y
If x > y
if x ≤ y
If x < y
If x = y or no relation can be established between x and y.
Explanation:

I. x²+20 = 9x

x²-9x+20=0

(x-4)(x-5)=0

x=4,5

II. y²+42=13y

y²-13y+42=0

(y-6)(y-7)=0

y=6,7

x<y

I. x²+5x+6=0

II. y²+7y+12=0
If x ≥ y
If x > y
if x ≤ y
If x < y
If x = y or no relation can be established between x and y.
Explanation:

I. x²+5x+6=0

(x+2)(x+3) = 0

x=-2,-3

II. y²+7y+12=0

(y+3)(y+4)=0

y=-3,-4

Manish bought 25 kg of rice at INR 32 per kg and 15 kg of rice at INR 36 per kg. What profit did he get when he mixed the two varieties together and sold it at INR 40.20 per kg
25%
40%
30%
20%
None of these
Explanation:

Total C.P. = 25×32+15×36 = INR 1340/-

Total S.P. = 40.20×(25+15)=INR 1608/-

Profit percentage = 1608-1340/1340 ×100 = 20%

Farah was married 8 years ago. Today her age is 1 2/7 times to that at the time of marriage. At present her daughter’s age is 1/6^th of her age. What was her daughter’s age 3 years ago
6 years
7years
3years
Cannot be determined
None of these
Explanation:

Let Farah's present age = x years

According to question,

(x-8)×1 2/7=x

x=9/7x-8×9/7

2/7x=72/7⇒x = 36 years

Farah's daughter's present age = 36×1/6

=6 years

3 years ago his daughter's age = 6-3 = 3 years

A horse is tothered to a peg with a 14 m long rope at the corner of a 40 m long and 24 m wide rectangular grass-field. What area of the field will the horse graze
154m²
308²
240²
480²
None of these
Explanation:

Required area = 1/4π(14)²

=1/4×22/7×14×14 = 154m²

From a well-shuffled pack of 52 playing cards, one card is drawn at random. What is the probability that the card drawn will be a black king
1/26
7/13
3/13
9/13
1/13
Explanation:

Required probability = 2/52 = 1/26

Directions (next five questions) : In the following table, the number of units manufactured and sold by five companies – P,Q,R,S and T has been given. Study the given data carefully and answer the questions

Company	Number of Units manufactured (in thousand)	Number of Units sold (in thousand)
P	35	20
Q	45	30
R	35	25
S	40	35
T	50	40

What is the respective ratio between the units manufactured by company P and company S
7:8
8:7
3:5
5:3
None of these
Explanation:

Required ratio = 35:40 = 7:8

What is the average number of units (in thousand) sold by all the companies together
25.7
30
27.7
28.8
None of these
Explanation:

Required average = 20+30+25+35+40/5 = 30

Which company sold highest percentage of units as compared to manufactured by it
Q
R
P
T
S
Explanation:

Percentage for

P = 20/35×100 = 57.14%

Q = 30/45×100 = 66.67%

R = 25/35×100 = 71.43%

S=35/40×100 = 87.5%

T = 40/50×100 = 80%

What is the respective ratio between the number of units sold by company S and that sold by company D
7:6
1:2
1:3
3:1
None of these
Explanation:

Required ratio = 35:30 = 7:6

What is the average number (in thousand) of units manufactured by all the companies together
41
40
43
44
46
Explanation:

Required average = 35+45+35+40+50/5 = 205/5 = 41

(2.0001)³×(1.999)^-2÷(3.999)^-4=?
32
16
64
256
512
Explanation:

? = 2³×2^-2÷4^-4 = 8×1/4×256 = 512

Directions (next five questions): What approximate value should come in the following questions at the question places (?). You are not required to calculate the exact value.

999.0001+899.999-349.88 = ?
1549
1560
1449
1460
None of these
Explanation:

? = 999+900 -350 = 1549

999.0001+899.999-349.88 = ?
1549
1560
1449
1460
None of these
Explanation:

? = 999+900 -350 = 1549

50.001%of 99.99÷49.999 = ?
1
0.1
0.01
0.02
None of these
Explanation:

? = 100×50/100 ÷50 = 1

55.003×54.998+5.001 = ?
3500
3630
2540
3030
2750
Explanation:

? = 55×55+5 = 3030

(13.001)³
1900
2200
2000
1800
2100
Explanation:

? = (13)3 = 2197 = 2200

Directions (next five questions) In the following table, the number of employees working in five companies and the corresponding ratio of male and female employees have been given. You are required to study the table carefully and answer the questions.

Company	Number of Employees
L	400
M	600
N	800
O	1000
P	1200
Company	Male : Female
L	12:8
M	15:5
N	4:1

O	13:12
P	7:5

The total number of male employees working in companies N and P together is :
1240
1360
1340
1260
None of these
Explanation:

Required number of males

= 800×4/5+1200×7/12

=1340

The number of female employees in company M is
450
150
250
350
None of these
Explanation:

Required number of females

= 600×5/20 = 150

What is the average number of employees in all companies together is :
800
775
760
600
None of these
Explanation:

Required average

=400+600+800+1000+1200/5

=4000/5 = 800

The number of female employees working in company O is what percent of total employees working in that company
24
12
48
13
None of these
Explanation:

Required percentage = 1000×12/25/1000 ×100 = 48%