Two stations, A and B are 827 km apart from each other. One train starts from station A at 5 a.m. and travel towards station B at 62 km/h. Another train starts from station B at 7 a.m. and travel towards station A at 59 km/h. At what time will they meet

- A1 p.m.
- B11:45 a.m.
- C12:30 a.m
- D11:30 a.m.
- E1:30 p.m.
**Explanation:**

One train starts from station A at 5 a.m. and travel towards station B at 62 km/h.

Distance covered in 2 hours = 2×62

=124 km

Remaining distance = 827-124

= 703 km

According to question,

62+59 = 703/t

t=703/121

t = 5 98/121 hours

Hence, they meet at [7+5 98/121] = 12 98/121 p.m.

= 1 p.m.

A 240 m long train running at the speed of 60 kmph will take how much time to cross another 270 m long train running in opposite direction at the speed of 48 kmph ?

- A17 sec
- B3 sec
- C12 sec
- D8 sec
- ENone of these
**Explanation:**Required time = Distance/Speed

=240+270/60+48×5/18 = 510/30 = 17 sec

A passenger train takes 1 hour less for a journey of 120 km, if its speed is increased by 10 km/hour from its usual speed. What is its usual speed

- A50 km/hour
- B40 km/hour
- C35 km/hour
- D30 km/hour

A man walking at 5 km / hour noticed that a 225 m long train coming in the opposite direction crossed him in 9 seconds. The speed of the train is

- A75 km/hour
- B80 km/hour
- C85 km/hour
- D90 km/hour

In what time will a 100 metre long train running with a speed of 50 km/hr cross a pillar

- A7.0 sec
- B72 sec
- C7.2 sec
- D70 sec

A train 220 m long is running at 30 km/hr. How long will it take to cross a bridge 80 meters long

- A10 seconds
- B14/3 seconds
- C36 seconds
- D16.8 seconds

If a man walks at the rate of 5 km/hour, he misses a train by 7 minutes. However, if he walks at the rate of 6km/hour, he reaches the station 5 minutes before the arrival of the train. The distance covered by him to reach the station is

- A6 km
- B7 km
- C4 km
- D6.25 km
**Explanation:**d/5-d/6 = 12/60 ⇒ d = 6 km.

Two places P and Q are 162 km apart. A train leaves P for Q and simultaneously another train leaves Q for P. They meet at the end of 6 hours. If the former train travels 8 km/hour faster then the other, then speed of train from Q is

- A9 1/2 km/hour
- B10 5/6 km/hour
- C12 5/6 km/hour
- D8 ½ km/hour
**Explanation:**Speed of train Q = S km/hr

⇒ 162/(S+8)+S = 7 ⇒ S = 9 1/2 km/hr.

Two places P and Q are 162 km apart. A train leaves P for Q and simultaneously another train leaves Q for P. They meet at the end of 6 hours. If the former train travels 8 km/hour faster than the other, then speed of train from Q is

- A12 5/6 km/hour
- B8 1/2 km/hour
- C10 5/6 km/hour
- D9 1/2 km/hour

A train starts from station A and reaches B 15 minutes late when it moves with 40 km/hr and 24 minutes late when it goes 30 km/hr. The distance between the two station is

- A16 km
- B18 km
- C21 km
- D24 km

A train covers a distance of 12 km in 10 minutes. If it takes 6 seconds to pass a telegraph post, then the length of the train is:

- A120 m
- B90 m
- C100 m
- D140 m

If a train maintains an average speed of 42 km per hour, it arrives at its destination at the right time, if however, the average speed is 40 km per hour, it arrives 15 minutes late. Find the length of the journey

- A210 km
- B205 km
- C209 km
- D200 km

A man travels 600 Km by train at 80 Km/hour, 600 Km by ship at 30 Km/hour, 500 Km by aeroplane at 400 Km/hour and 300 Km by car at 60 Km/hour. What is the average speed(Km/hour) for the entire distance

- A63
- B62 7/27
- C56 7/27
- D59 7/27

Train A which is 320 m long can cross a pole in 16 sec. If it halts 5 times each time for exactly 18 min. how many hours it will take to cover a distance of 576 km? (in hours)

- A8
- B10 ½
- C8 ½
- D9
- E9 ½
**Explanation:**Speed of train = 320/16

=20 m/sec

=20×18/5=72 km/h

∴ Required time to cover a distance of 576 km

= 5×18/60+576/72

=1.5+8

=9.5 hours

A 476 m long moving train crosses a pole in 14 sec. The length of a platform is equal to the distance covered by the train in 20 sec. A man crosses the same platform in 7 m and 5 sec. What is the speed of the man in m/s

- A1.8 m/s
- B1.4 m/s
- C1.6 m/s
- D2 m/s
- E1.2 m/s
**Explanation:**Speed of the train = 476/14 = 34m/s

Length of the platform = 34×20

= 680 m

∴ Speed of the man = 680/425 = 1.6 m/s

The Delhi bound train reaches Delhi in 6 hours after its start. If a person travels to Mathura from Delhi which takes two more hours (including the transition time) from Delhi, at what time will he reach Mathura

- A1 am next day
- B10 pm in the night
- C12 O’ clock midnight
- D2 am next day
- E11 pm in the night

Which train leaves exactly 3 hours after the Chennai bound train on its scheduled day

- AThe Kanpur bound train
- BThe train which leaves on Monday
- CThe train which leaves on Sunday
- DThe train which leaves at 7 pm
- EThe Surat bound train

Two trains running in opposite directions cross a man standing on the platform in 27 sec and 17 sec respectively and they cross each other in 23 sec. What is the ratio of their speeds

- A1:3
- B3:2
- C3:4
- D1:2
- E2:1
**Explanation:**Let the speed of train

_{1}=v_{1}and the length of train

_{1=}d_{1}Let the speed of train

_{2=}d_{2}and the distance of train

_{2=}d_{2}According to question,

27=d

_{1/}v_{1}d

_{1=}27×v_{1 ....(i)}17=d

_{2/}v_{2}d

_{2}=17×v_{2 .....(ii)}Again, according to question,

23=17v

_{2+}27v_{1/}v_{1+}v_{2}23v

_{1+}23v_{2=}17v_{2+}27v_{1}4v

_{1}=6v_{2}v

_{1}/v_{2=}6/4v

_{1:}v_{2 = }3:2

A train with speed 81Km/hr passes a man with six seconds. Then the length of the train is

- A140m
- B135m
- C130m
- D125m
**Explanation:**Length of the train = 81×5/18×6 =135m.

A train 110m in length runs through a station at the rate of 36km per hour. How long will it take to pass a given point?

- A12 Sec.
- B11 Sec.
- C13 Sec.
- D15 Sec.
**Explanation:**Time = Distance / Speed

= 110/36×5/18

= 110/10

=

**11 Sec.**

Find the time taken by a 180 m long train running at 54 km/hr to cross a man standing on a platform

- A4 seconds
- B12 seconds
- C30 seconds
- D15 seconds

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