Arithmetic Aptitude Questions & Answers (Compiled from UPSC, SSC ,PSC ,IBPS previous question papers)

Directions (Next Six Questions) : study the table and answer the given questions.

Advertisement revenues (in INR Thousand)generated

from printed version (PV) and online version (OV) of

6 magazines during 6 months

Month	Magazine P		Magazine Q		Magazine R		Magazine S		Magazine T		Magazine U
Month	PV	OV	PV	OV	PV	OV	PV	OV	PV	OV	PV	OV
Jan.	169	163	201	145	136	141	209	168	152	209	131	184
Feb.	144	171	157	139	156	149	132	223	186	217	98	190
Mar.	129	148	204	144	152	174	174	164	116	185	118	219
Apr.	163	139	232	139	168	207	148	172	129	156	174	236
May	113	152	128	151	196	209	132	211	187	139	168	111
June	172	141	142	163	178	243	211	177	154	144	151	194

What is the respective ratio between total advertisement revenues generated from online version of all the given magazines together in February and total advertisement revenues generated from printed version of all the given magazine together in May ?
33:28
39:28
27:16
33:20
27:22
Explanation:

Required ratio = 1089:924 = 33:28

The respective ratio of advertisement revenues generated from printed version by magazine P to advertisement revenues generated from online version by the same magazine in July is same as the respective ratio of advertisement revenues generated from printed version by Magazine Q to advertisement revenues generated from online version by the same magazine in March. If the advertisement revenue generated from online version by Magazine P in July was INR 1,08,000/-, what was the advertisement revenue generated from printed version by the same magazine in July ?
INR 1,87,000/-
INR 1,53,000/-
INR 1,36,000/-
INR 1,70,000/-
INR 1,19,000/-
Explanation:

Total advertisement revenue generated from printed version = 108000 ×204/144 = 1,53,000/-

Sixteen men and twelve women together can complete a work in 8 days. Twenty men can complete the same work in 16 days. How many days will sixteen women take to complete the same work ?
40 days
30 days
24 days
20 days
10 days
Explanation:

According to question,

By formula , M₁D₁ = M₂D₂

(16M+12W) 8 =(20M) 16

16M + 12W = 40M

24M = 12W

2M=100

16 women = 16×2 = 32 M

Again M₁D₁ = M₂D₂

32×D₁=16×20

D₁=10 days

The sum of two numbers is 6more than twice the smaller number. If the difference between these two numbers is 6, what is definitely the smaller number ?
18
20
Data provided are not adequate to answer the question
12
24
Explanation:

Let the smaller number be y and larger number be x.

according to question,

x+y=6+2y

x-y=6 →(1)

x-y=6 →(2)

Equations (1) and (2) cannot be solved.

Directions (Next Five Questions) : Study the following information in the passage and answer the given questions.

There are 19000 students in college ‘P’. Each of them are studying either one or more of the given languages—Japanese, Korean and Latin. The respective ratio of male and female students is 9:11

14% of the male students study only Japanese, 12% study only Korean and 20% study only Latin. 16% of the male students study only Japanese and Korean, 22% Study only Korean and Latin and 8% study only Japanese and Latin. The remaining male students study all the given languages. 22% of the female students study only Japanese, 18% study only Korean and 20% study only Latin. 12% of the female students study only Japanese and Korean, 16% study only Korean and Latin and 10% study only Japanese and Latin. The remaining female students study all the given languages.

Number of male students who do not study Korean is what percent of the number of female students in college P ?
34 4/11%
37 1/11%
38 2/11%
33 3/11%
32 4/11%
Explanation:

Total students = 19000

Total Boys = 8550

Total Girls = 10450

Number of male students who do not study Korean = 1197+1710+684 = 3591

Total number of female students = 10450

Required percentage = 3591/10450 ×100

= 34 4/11%

What is the difference between number of female students who study Latin and number of male students who study the same ?
43
76
83
62
57
Explanation:

Total students = 19000

Total Boys = 8550

Total Girls = 10450

Number of female students who study Latin = 209+1672+2090+1045 =5016

Number of male students who study Latin = 684 +1881 + 1710 + 684 = 4959

Required difference = 5016-4959 = 57

What is the respective ratio between number of male students who study Korean and number of female students who study the same ?
58:59
57:58
87:88
63:64
61:62
Explanation:

Required ratio = 4959/5016

=87/88

How many male students study Japanese ?
3889
3572
3933
3782
3258
Explanation:

Total students = 19000

Total Boys = 8550

Total Girls = 10450

JApanese male Students = 1197+1368+684+684

= 3933

Number of male students who study more than one of the given languages is what percent is more than the number of female students who study more than one of the given languages?
12 2/13%
10 5/11%
10 1/11%
18 1/13%
13 1/11%
Explanation:

Total students = 19000

Total Boys = 8550

Total Girls = 10450

Number of male students = 4617

Number of Female students = 4180

Required Percentage = (4617-4180/4180×100)%

= 10 5/11%

The ratio between the base and height of a right angled triangle is 4:5 respectively. If the area of the right angled triangle is 80 sq cm, what is the height of the triangle?
16√2cm
10cm
8cm
20cm
10√2cm
Explanation:

Let the base and height of a right angled triangle be 4x and 5x respectively.

By formula,

Area of right angled triangle = ½×Base ×Height

80=½ ×4x × 5x

x² = 8

x = 2√2cm

∴ Height = 5x = 5× 2√2cm

= 10√2cm

One- fourth of two-fifth of 30 percent of a number is 15. What is 20 percent of that number ?
100
50
Data provided are not adequate to answer the question
200
75
Explanation:

Let the number be x.

According to question,

1/4×2/5×30% of x=15

1/4×2/5×30/100×x=15

∴ x = 500

20 Percent of that number = 20% of x

= 20/100 ×500

= 100

Directions (Next Five Questions) : What approximate value will come in place of the question mark(?) in the given questions ? (you are not expected to calculate exact value)

12.95×7.05+85.01²×10.99=?
77586
77776
79566
78356
76876
Explanation:

? = 12.95×7.05+85.012×10.99

? ≈ 13×7+85×85×11

? ≈ 91+79475

? ≈ 79566

17.99²-14.05²+(2343.75+81.55)÷?=229
32
39
24
28
12
Explanation:

17.99²-14.05²+(2343.75+81.55) ÷? = 229

324-196+2426÷? = 229

? = 2426/101

= 24.01

≈24

423.62-269.21+(11.9% of 78)=?
525
455
645
395
275
Explanation:

solution,

? = 423.62-269.21÷(11.9% of 78)

? = 423.62-269.21÷(11.9/100×78)

? = 424-269 ÷9.282

? = 424-30=394≈395

3/5 of 7/19 of 15/28 of 543=?
88
44
72
50
64
Explanation:

3/5 × 7/19 × 15/28 × 543 =?

? = 64.30 ≈64

899.99+45.012 ? -224.488
185
395
295
245
355
Explanation:

900÷45 = ?-225

20≈ ?-225

? ≈ 225 + 20

? ≈ 245

The difference between the simple interest and the compound interest compounded annually at the same rate of interest on a sum of money at the end of two years is INR 50/-. What is definitely the rate of interest percent per annum?
10%
4%
Data provided are not adequate to answer the question
5%
7.5%
Explanation:

Let the rate of interest be INR x.

Difference between SI and CI = INR 50/-

Applying formula,

Difference = PR²/100²

But P is not provided. Therefore, we cannot solve it due to insufficient data.

The total present ages of P and Q is 25 years more than the present age of R. If present age of Q is 5 years older than R, what is P’s present age ? ( In years)
20
Data provided are not adequate to answer the question
40
35
30
Explanation:

Present age of P+Q = 25+R →(1)

and Q = 5+R

∴ Q-R =5 →(2)

From equation (1) we get,

P+Q-R=25

Putting the value of equation (2) in equation (1)

∴ P+5=25

P = 20Years

A’s monthly income INR 10,000/- less than B’s monthly income. B’s monthly income is INR 15,000/- less than C’s monthly income. If the total monthly income of A,B and C together is INR 65,000/-, what is A’s monthly income ?
INR 10,000/-
INR 15,000/-
INR 20,000/-
None of the answers given is correct
INR 5,000/-
Explanation:

Let C's monthly income is INR x.

∴ B's monthly income = INR(x-15000)

∴ A's monthly income = (x-15000)-10000

=INR (x-25000)

∴ Total monthly income of A, B and C together

=x+(x-15000)+(x-25000)

3x-40000=65000

3x=65000+40000

x=35000

∴ A's monthly income = x-25000

= 35000-25000

=INR 10,000/-

The numerical value of area of a rectangular field is 90 times the numerical value of its breadth. If the perimeter of the filed is 240m, what is the breadth of the field ?
60m
Data provided are not adequate to answer the question
30m
20m
15m
Explanation:

Area of rectangular field= L×B

∴ L × B = 90×B ⇒ L =90m

Perimeter of the field = 2(L+B)

∴ 2(L+B) = 240

L+B = 120

∴ 90+B=120

B=120-90

=30m

Directions (Next Five Questions)) : Refer to the table and answer the given questions.

Data related to number of employees in Six Companies during 6 years

Companies	I		J		K		L		T		N
Gender/Year	M	F	M	F	M	F	M	F	M	F	M	F
2004	142	136	144	111	138	97	162	145	148	121	145	118
2005	165	171	161	136	194	134	219	183	180	178	212	177
2006	139	145	164	157	152	129	178	191	212	162	241	184
2007	217	198	179	211	254	168	277	234	263	198	333	259
2008	265	232	348	356	238	278	298	313	310	216	321	316
2009	372	242	321	238	281	267	245	214	396	230	339	303

Note : M = Male : F = Female

What is the respective ratio between total number of employees (male and female) in companies J,K and N together in 2005 and total number of employees (male and female) in the same companies together in 2007?
11:16
13:16
9:14
11:18
13:18
Explanation:

Total number of employees in companies J,K and N together in 2005 = 1014

Total number of employees in companies J,K and N together in 2007 = 1404

∴ Required ratio = 1014:1404

= 13:18

Total number female employees in company J during all the given years together is what percent of the total number of male employees in Company I during all the given years together ?
87%
93%
89%
91%
95%
Explanation:

Total number of female employees in company J = 1209

Total number of male employees in company I = 1300

∴ Required Percentage = 1209/1300×100

= 93%

In which of the given years is percentage increase in the number of male employees of Company T from previous year the highest ?
2009
2007
2008
2005
2006
Explanation:

For company T,

Percentage increase in 2004-2005

=180-148/148×100

=21.62%

Percentage increase in 2005-2006

= 212-180/180 ×100

=17.77%

Percentage increase in 2006-2007

= 263-212/212×100

=24.05%

Percentage increase in 2007-2008

= 310-263/263×100

=17.87%

Percentage increase in 2008-2009

= 396-310/310×100

= 27.74%

Total number of female employees in company L in 2004, 2005, 2006 and 2007 together is what percent more than the total number of female employees in company T in the same years together ? (Rounded off to nearest integer)
20%
14%
18%
12%
16%
Explanation:

Total number of female employees in company L = 753

Total number of female employees in company T = 659

∴ Required Percentage = 753-659/659 ×100

=14%

What is the difference between average number of male employees in all the given companies in 2006 and average number of female employees in all the given companies in 2009?
68
64
58
52
74
Explanation:

Total number of male employees in 2006 = 1086

∴ Average = 1086/6 = 181

Total number of female employees in 2009 = 1494

∴ Average = 1494/6 = 249

∴ Required difference = 249-181 = 68

Directions (Next Five Questions) : what will come in place of the question mark (?) in the given number series ?

2 4 10 ? 82 244
28
30
46
48
34
Explanation:

Solution : 2×3-2 = 4

4×3-2 = 10

10×3-2 = 28

28×3-2 = 82

82×3-2 = 244

44 ? 99 148.5 222.75 334.125
72
77
66
54
84
Explanation:

Solution is,

44×1.5 = 66

66×1.5 = 99

99×1.5 = 148.5

148.5×1.5 = 222.75

222.75×1.5 = 334.125

20 23 30 43 64 ?
85
92
95
99
88
Explanation:

33 16.5 ? 24.75 49.5 123.75
16.5
13.5
22.5
20.5
12.5
Explanation:

Solution is,

33×0.5 =16.5

16.5×1 =16.5

16.5×1.5 =24.75

24.75×2 =49.5

49.5×2.5 =123.75

3600 1800 600 150 30 ?
10
5
6
15
7.5
Explanation:

3600÷2 = 1800

1800÷3 = 600

600÷4 =150

150÷5=30

30÷6=5

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