A boat man goes 4 Km against the current of the stream in 1hour and goes 2 Km along the current in 5 minutes. How long will it take to go 21 Km in stationary water
In an hour a boat goes 10 Km along the stream and 4 Km against the stream. The speed of the boat in still water (in Kmph) is:
speed of stream = X Kmph and the speed of water = 8 Kmph X + Y = 10 X - Y = 4 X = 7, Y = 3 Speed of stream = 7 Kmph
A boat can travel 8 Km an hour in still water, but it takes thrice as much time for travelling the same distance against the current. The speed of the current (in Kmph) is:
A man can row 8 Kmph in still water. If the velocity of the current is 2 Kmph and it takes him 2 hours to row to a place and come back. How far is the place
8 + 2 = 10 kmph
8 - 2 = 6 kmph
required distance be X km
Then X/10+X/6 = 2
3X + 5X = 60 8X = 60 X = 7.5 km
A man rows to a place 48 Km distance and back in 14 hours. He finds that he can row 4 Km with the stream in the same time 3 Km against the stream. The rate off the stream is
48/4/X + 48/3/X = 14 12X + 16X =14 X = 1/2 Speed in downstream = 8 Kmph Speed in up stream = 6 Kmph Then the Rate of stream = 1/2 (8 - 6) = 1 Kmph
In a stream running at 2 Kmph, a motor boat goes 10 Km upstream and back again to the starting point in 55 minutes. Find the speed of motor boat in still water
speed in downstream = (X + 2) km
speed in upstream = (X - 2) kmph
10/X+2 + 10/X-2 = 55/60 11X2 - 240X - 44 = 0 (X - 22)(11x + 2) = 0 X = 22 or X = -2/11 Then X = 22 kmph
A man can row 24 kmph in still water. It takes him thrice as long to row up as to row down the river. Find the rate of the stream?
Rate of upstream = X kmph
Rate of down stream = 3 x kmph
Rate of still water = (3x+x)2 = 2x
2x = 24
x = 12
Rate of upstream = 12
Rate of downstream = 36
Rate of stream = 36-12/2 = 12 kmph