If n is a natural number and n=p1^x1*p2^x2*p3^x3,where p1,p2 and p3 are distinct prime factors,then number of prime factors of n is

  • x1+x2+x3
  • x1 x2 x3
  • (x1+1)(x2+1)(x3+1)
  • None of the above
If n is a natural number and n=p1^x1*p2^x2*p3^x3,where p1,p2 and p3 are distinct prime factors,then
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