I.                     x2 +8x+15=0

    II                     y2+3y+2=0

  • If x > y
  • If x≤y
  • If x ≥ y
  • If x < y
  • If relationship between x and y cannot be determined
  • Explanation:

    I. x2+8x+15=0

    x2+5x+3x+15=0

    x(x+5)+3(x+5)=0

    (x+3)(x+5)=

    ⇒        x=-3,-5

    II. y2+3y+2=0

    y2+2y+y+2=0

    y(y+2)+1(y+2)=0

    (y+1)(y+2)=0

    ⇒       y=-1,-2

    ஃ x


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I.                     x2 +8x+15=0 II   &nbs
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