I.  4x2+16x+15=0

    II.  2y2+3y+1=0

  • If relationship between x and y cannot be established.
  • If x≤y
  • If x≥y
  • If x
  • If x>y
  • Explanation:

    I.      4x2+16x+15=0

    4x2+10x+6x+15=0

    2x(2x+5)+3(2x+5)=0

    (2x+3)(2x+5) =0

    x =-3/2, -5/2

    II.    2y2+3y+1=0

    2y2+2y+y+1=0

    2y(y+1)+1(y+1) = 0

    (2y+1)(y+1) =0

    y=-1/2, -1

    So x

     

     

Related Question & Answers

I.  4x2+16x+15=0 II.  2y2+3y+1=0
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