I. 2x2+11x+14=0

    II. 2y2+15y+28=0

  • If x
  • If x>y
  • If x≥y
  • If x≤y
  • If relationship between x and y cannot be established.
  • Explanation:

    I. 2x2+11x+14=0

    2x2+7x+4x+14=0

    x(2x+7)+2(2x+7)=0

    (x+2)(2x+7) = 0

    x=-2, -7/2

    II. 2y2+15y+28=0

    2y2+7y+8y+28=0

    y(2y+7)+4(2y+7) =0

    y =-4, -7/2

    So, x≥y

     

     

I. 2x2+11x+14=0 II. 2y2+15y+28=0
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