I. x2+7x+12=0

    II. Y2+6y+8=0

  • If x>y
  • If x≥y
  • If x
  • If x≤y
  • If x=y or the relationship cannot be established.
  • Explanation:

    Solution,

     I. x2+7x+12=0

    x2+4x+3x+12=0

    x(x+4)+3(x+4)=0

    (x+3)(x+4)=0

    x=-3,-4

    II. y2+6y+8=0

    y2+4y+2y+8=0

    y(y+4)+2(y+4)=0

    (y+4)(y+2)=0

    y=-4,-2

    ∴ x≤y


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 I. x2+7x+12=0 II. Y2+6y+8=0
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