I. 2x2+15x+27=0

    II. 2y2+7y+6=0

  • x ≤ y
  • x ≥ y
  • Relationship between x and y cannot be established
  • x < y
  • x > y
  • Explanation:

    I. 2x2+15x+27=0

    ⇒ 2x2+9x+6x+27=0

    ⇒ x(2x+9)3(2x+9)=0

    ⇒ (x+3)(2x+9)=0

    ⇒                      x=-9/2,-3

    II. 2y2+7y+6=0

    ⇒ 2y2+4y+3y+6=0

    ⇒ 2y(y+2)+3(y+2)=0

    ⇒ (y+2) (2y+3) = 0

    ⇒                       y=-2,-3/2

    ∴                       x < y

Related Question & Answers

I. 2x2+15x+27=0 II. 2y2+7y+6=0
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