I. 2x2-15x+27=0

    II. 5y2-26y+33=0

  • x ≥ y
  • If x ≤ y
  • If x > y
  • If x < y
  • If relation between x and y cannot be established.
  • Explanation:

     I. 2x2-15x+27=0

    2x2-9x-6x+27=0

    x(2x-9)-3(2x-9)=0

    (x-3)(2x-9)=0

    x=3,9/2

    II. 5y2-26y+33=0

    5y2-15y-11y+33=0

    5y(y-3)-11(y-3)=0

    (y-3)(5y-11)=0

    y=11/5,3

    ∴ x ≥ y

 I. 2x2-15x+27=0 II. 5y2-26y+33=0
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