I. x2+x-12=0             

    II. y2+2y-8=0

  • If x ≤ y
  • Ifx ≥ y
  • If relationship between x and y can not be established
  • If x < y
  • If x > y
  • Explanation:

     I. x2+x-12=0             

     x2+4x-3x-12=0

    x(x+4)-3(x+4)=0

    (x-3)(x+4)=0

    x=3,-4

    II. y2+2y-8=0

    y2+4y-2y-8=0

    y(y+4)-2(y+4)=0

    (y-2)(y+4)=0

    y=2,-4

    ∴ x ≥ y

 I. x2+x-12=0              II. y2+2y-8=0
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