Let x ~ Binomial (5,0.6) and Y ~ Poisson (2) be independent. Then P(xy = 0) equals :

  •  e-­2. (0.4)-5
  •  e-­2+(0.4)-5
  •  e-­2+(0.4)-5- e-­2.(0.4)-5
  •  e-­2. (0.6)-5+(1- e-­2)(0.4)-5
 Let x ~ Binomial (5,0.6) and Y ~ Poisson (2) 
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