If x is a continuous random variable with p.d.f.
ƒ(x) = 1/√2∏ exp (-x2/2), -∞ < x < ∞
and y is defined as y = x+1, then E(y) equals:
If a variable has three values k, 0 and 3k with corresponding frequencies as 3k, 2k and k respectively, then the value of coefficient of skewness b1 is :
The joint distribution of x and y is as follows
Then E(x|y=1) is :
The mean and standard deviation of a variable x are 36 and 4 respectively. Then the mean and standard deviation of [50 (x/4)], respectively are :
Let x ~ Binomial (5,0.6) and Y ~ Poisson (2) be independent. Then P(xy = 0) equals :
In a negatively skewed distribution