I. 4x2+17x+15=0

    II. 3y2+19y+28=0

  • If x ≥ y
  • If x ≤ y
  • If x > y
  • If x < y
  • If relationship between x and y cannot be establishment
  • Explanation:

    I. 4x2+17x+15=0

    4x2+12x+5x+15=0

    4x(x+3)+5(x+3)=0

    (4x+5) (x+3)=0

    x=-5,-3

    II. 3y2+19y+28=0

     3y2+12y+7y+28=0

    3y(y+4)+7(y+4)=0

    (3y+7)(y+4)=0

    ∴ y = -7/3,-4

    Hence, relationship between x and y cannot be established.

Related Question & Answers

I. 4x2+17x+15=0 II. 3y2+19y+28=0  
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