I. 3x2+11x+10=0

    II. 2y2+13y+21=0

  • If x ≥ y
  • If x ≤ y
  • If x > y
  • If x < y
  • If relationship between x and y cannot be establishment
  • Explanation:

    I. 3x2+11x+10=0

    3x2+6x+5x+10=0

    3x(x+2)+5(x+2)=0

    (3x+5)(x+2) = 0

    ∴ x=-5/3,-2

    II. 2y2+13y+21=0

    2y2+7y+6y+21=0

    y(2y+7)+3(2y+7)=0

    (y+3)(2y+7)=0

    ∴ y=-3, -7/2

    Hence , x > y

Related Question & Answers

I. 3x2+11x+10=0 II. 2y2+13y+21=0
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