I. 3x2+13x+14=0

    II. 8y2+26y+21=0

  • If x ≥ y
  • If x ≤ y
  • If x > y
  • If x < y
  • If relationship between x and y cannot be establishment
  • Explanation:

    I. 3x2+13x+14=0

    3x2+7x+6x+14=0

    x(3x+7)+2(3x+7)=0

    (x+2)(3x+7)=0

    x=-2,-7/3

    II. 8y2+26y+21=0

    8y2+14y+12y+21=0

    2y(4y+7)+3(4y+7)=0

    (2y+3)(4y+7)=0

    y=-3/2, -7/4

    Hence x < y

Related Question & Answers

I. 3x2+13x+14=0 II. 8y2+26y+21=0
Home Ask Questions Study Current Affairs Previous Papers Kerala PSCIBPSUPSCRBITNPSCMPSCSSCCBSEUnited StatesModel Tests News More Answers Coaching Centres Careers Downloads Colleges