I. 4x2-29x+45=0

    II. 3y2-19y+28=0

  • If x < y
  • If x > y
  • If x ≥ y
  • If x ≥ y
  • If relationship between x and y cannot be established
  • Explanation:

    I. 4x2-29x+45=0

    4x2-20x-9x+45=0

    4x(x-5)-9(x-5)=0

    (4x-9)(x-5) = 0

    x=9/4 or 5

    II. 3y2-19y+28=0

     3y2-12y-7y+28=0

    3y(y-4)-7(y-4)=0

    (3y-7)(y-4)=0

    y=7/3 or 4

    ∴ relationship between x and y cannot be established

Related Question & Answers

I. 4x2-29x+45=0 II. 3y2-19y+28=0
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