A vessel contains a mixture of milk and water in the respective ratio of 14:3.25.5 litre of the mixture is taken out from the vessel and 2.5 litre of pure water and 5 litre of pure milk is added to the mixture. If the resultant mixture contains 20% water, what was the initial quantity of mixture in the vessel before the replacement ? (in litre)
- 51
- 102
- 68
- 85
- 34
- Explanation:
Let the quantity of milk in vessel = 14x
Let the quantity of water in vessel = 3x
According to question,
14x-25.5×14/17+5÷3x-25.5×3/17+2.5 =80/20
14x-21+5/3x-4.5+2.5 = 4/1
14x-16x=12x-8
2x=8
x=4
∴ quantity of mixture in vessel = 17x⇒17×4
= 68 litre