If a=√2+1 and b= 1/√2+1 then the value of  a3-b3/a2+b2+ab

  • √2-1
  • 0
  • 2
  • 2√2
  • Explanation:

    Given that  a=  √2+1  and  b=  1

                                                √2+1

    a3-b3= (a-b) (a2+ab+b2)

    a3-b3/a2+b2+ab = (a-b)

    a3-b3/a2+b2+ab = √2+1-1/√2+1

    (√2+1)2-1/√2+1

    2+2√2+1-1/√2+1

    3-1+2√2/√2+1

    2+2√2/√2+1

    2(1+√2)/1+√2 =2

     

If a=√2+1 and b= 1/√2+1 then the value of  a3-b3/a2+b2+ab
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