I. 5x2+20x+20=0

    II. 25y2+25y+6=0

  • If x ≥ y
  • If x ≤ y
  • If x
  • If x>y
  • Relationship between x and y cannot be determined
  • Explanation:

    I. 5x2+20x+20=0

    5x2+10x+10x+20=0

    5x(x+2)+10(x+2)=0

    (5x+10)(x+2)=0

    x=-10/5 = -2,-2

    II. 25y2+25y+6=0

    25y2+15y+10y+6=0

    5y(5y+3)+2(5y+3)=0

    (5y+2)(5y+3)=0

    y=-2/5,-3/5

    Hence , x

     

     

     

     

Related Question & Answers

I. 5x2+20x+20=0 II. 25y2+25y+6=0
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