SBI Probationary Officer Exam Solved Question Paper - 21-06-2015

  • Question 6 :
  • The central theme of the given passage is ............

  • The shrinking market
  • Shift towards offering luxury goods to consumers
  • Products to offer consumers with squeezed pockets
  • To highlight products consumed by the middle class
  • Gaining insight into changing consumer behaviour towards CPGs
  • Question 15 :
  • Which of the following is true in the context of the passage

  • In the U.S., during the three year period after 2009, small manufactures did not fare well as compared to their larger counterparts.
  • Impact on disposable incomes of people barely affects the CPG manufacturing industry.
  • Post-tax wages, especially for the middle class, are one of the critical factors which have reduced spending behavior of consumers.
  • CPG have always been a favourite among consumers.
  • None of the given options is true
  • Question 26 :
  • QST # 26

  • much
  • low
  • required
  • tough
  • minimal
  • Question 27 :
  • QST # 27

  • represent
  • sufficient
  • adequate
  • amount
  • deliver
  • Question 28 :
  • QST # 28

  • run
  • happens
  • plans
  • effect
  • hurt
  • Question 29 :
  • QST # 29

  • ample
  • fix
  • worst
  • frequent
  • paucity
  • Question 30 :
  • QST # 30

  • lack
  • solve
  • waste
  • exploit
  • advantage
  • Question 32 :
  • I. 4x2+17x+15=0

    II. 3y2+19y+28=0

  • If x ≥ y
  • If x ≤ y
  • If x > y
  • If x < y
  • If relationship between x and y cannot be establishment
  • Explanation:

    I. 4x2+17x+15=0

    4x2+12x+5x+15=0

    4x(x+3)+5(x+3)=0

    (4x+5) (x+3)=0

    x=-5,-3

    II. 3y2+19y+28=0

     3y2+12y+7y+28=0

    3y(y+4)+7(y+4)=0

    (3y+7)(y+4)=0

    ∴ y = -7/3,-4

    Hence, relationship between x and y cannot be established.

  • Question 33 :
  • I. 3x2+17x+22=0

    II. 5y2-21y+22=0

  • If x ≥ y
  • If x ≤ y
  • If x > y
  • If x < y
  • If relationship between x and y cannot be establishment
  • Explanation:

    I. 3x2+17x+22=0

    3x2+11x-6x+22=0

    x(3x-11)2(3x-11)=0

    (x-2)(3x-11)=0

    x=2,11/3

    II. 5y2-21y+22=0

    5y2-11y-10y+22=0

    y(5y-11)-2(5y-11)=0

    (y-2)(5y-11)=0

    ∴ y = 2,11/5

    Hence, 

  • Question 34 :
  • I. 3x2+11x+10=0

    II. 2y2+13y+21=0

  • If x ≥ y
  • If x ≤ y
  • If x > y
  • If x < y
  • If relationship between x and y cannot be establishment
  • Explanation:

    I. 3x2+11x+10=0

    3x2+6x+5x+10=0

    3x(x+2)+5(x+2)=0

    (3x+5)(x+2) = 0

    ∴ x=-5/3,-2

    II. 2y2+13y+21=0

    2y2+7y+6y+21=0

    y(2y+7)+3(2y+7)=0

    (y+3)(2y+7)=0

    ∴ y=-3, -7/2

    Hence , x > y

  • Question 35 :
  • I. 3x2+13x+14=0

    II. 8y2+26y+21=0

  • If x ≥ y
  • If x ≤ y
  • If x > y
  • If x < y
  • If relationship between x and y cannot be establishment
  • Explanation:

    I. 3x2+13x+14=0

    3x2+7x+6x+14=0

    x(3x+7)+2(3x+7)=0

    (x+2)(3x+7)=0

    x=-2,-7/3

    II. 8y2+26y+21=0

    8y2+14y+12y+21=0

    2y(4y+7)+3(4y+7)=0

    (2y+3)(4y+7)=0

    y=-3/2, -7/4

    Hence x < y

  • Question 36 :
  • I. 3x2-14x+15=0

    II. 15y2-34y+15=0

  • If x ≥ y
  • If x ≤ y
  • If x > y
  • If x < y
  • If relationship between x and y cannot be establishment
  • Explanation:

    I. 3x2-14x+15=0

    3x2-9x-5x+15=0

    3x(x-3)-5(x-3)=0

    (3x-5)(x-3)=0

    ∴ x=5/3,3

    II. 15y2-34y+15=0

    15y2-25y-9y+15=0

    5y(3y-5)-3(3y-5)=0

    (5y-3)(3y-5)=0

    ∴ y = 3/5,5/3

    Hence, x ≥ y

  • Question 42 :
  • 6399×1 3/8+353÷? = 10444

  • 14
  • 22
  • 2
  • 16
  • 8
  • Explanation:

    6400×13/8+353÷?=10444

    10400+353÷?=10444

    353÷?=44

    353/44=?

    ? = 8.02 = 8

  • Question 49 :
  • 19 20 16 25 9 ?

  • 32
  • 38
  • 34
  • 42
  • 48
  • Explanation:

    19+(1)220-(2)216+(3)225-(4)29+(5)234

  • Question 83 :
  • Statements : L = P≤W<V≤K≥Q;B<L;K=M

    Conclusions : I. L≥Q

                       II. W=M

  • If only conclusion I is true
  • If only conclusion II is true
  • If either conclusion I or II true
  • If neither conclusion I nor II is true
  • If both conclusions I and II are true
  • Explanation:

    Statements :B<L=P≤W<V≤K≥Q

                                            ⇓

                                            M

    Conclusions : I. L≥Q →False

                       II. W=M →False

     

SBI Probationary Officer Exam Solved Question Paper - 21-06-2015
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