I. x2-10x+24=0

    II. 3y2-19y+28=0

  • If x≥y
  • If x≤y
  • If x > y
  • If x
  • If relationship between x and y cannot be established
  • Explanation:

    I. x2-10x+24=0

    x2-6x-4x+24=0

    x(x-6)-4(x-6)=0

    (x-4)(x-6)=0

    x=4, 6

    II. 3y2-19y+28=0

    3y2-12y-7y+28=0

    3y(y-4)-7(y-4)=0

    (y-4)(3y-7)=0

    y=4, 7/3

    ∴ x≥y

     

I. x2-10x+24=0 II. 3y2-19y+28=0
Home Ask Questions Study Current Affairs Previous Papers Kerala PSCIBPSUPSCRBITNPSCMPSCSSCCBSEUnited StatesModel Tests News More Answers Coaching Centres Careers Downloads Colleges