A vessel contains 100 litre mixture of milk and water in the respective ratio 22 : 3. 40 litre of the mixture is taken out from the vessel and 4.8 litre of each pure milk and pure water is added to mixture. By what percent is the quantity of water in the final mixture less than the quantity of milk
Explanation:
Remaining mixture in vessel = 100-40 = 60 litre
Quantity of milk = 60×22/25 = 52.8 litre
Quantity of water = 60-52.8 = 7.2 litre
4.8 litre of each pure milk and pure water is added to the mixture.
Then,
Quantity of milk = 52.8+4.8 = 57.6 litre
Quantity of water = 7.2+4.8 = 12 litre
∴ Required percentage = 57.6-12/57.6×100
=45.6/57.6×100 = 79 1/6%
500-16=484
