A vessel contains a mixture of milk and water in the respective ratio 3:1. 32 litre of mixture was taken out and replaced with the same quantity of milk so that the resultant ratio between the quantities of milk and water in the mixture was 4 : 1 respectively. If 10 litre of mixture is again taken out from the vessel. What is the resultant quantity of water in the mixture ? (in litre)
Explanation:
Let the total quantity of mixture = x litre
According to question, 4/4+1=(x-32/x)
4x = 5x-160
x = 160 litre
The quantity of milk in mixture = 160 ×3/4
= 120 litre
The quantity of water in mixture = 160×¼= 40 litre
32 litre of mixture was taken out and replaced with the same quantity of milk.
Then, the quantity of milk in mixture
= 120-32×¾+32
= 120 -24+32
= 128 litre
The quantity of water in mixture = 40-32×¼ = 40-8
= 32 litre
New ratio of milk and water = 128:32 = 4:1
After 10 litres of mixture is again taken out from the vessel, The resultant quantity of water in the mixture = 32-10×1/5 = 32-2
= 30 litre
