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    A vessel contains a mixture of milk and water in the respective ratio of 14:3.25.5 litre of the mixture is taken out from the vessel and 2.5 litre of pure water and 5 litre of pure milk is added to the mixture. If the resultant mixture contains 20% water, what was the initial quantity of mixture in the vessel before the replacement ? (in litre)

  • 51
  • 102
  • 68
  • 85
  • 34
  • Explanation:

    Let the quantity of milk in vessel = 14x

    Let the quantity of water in vessel = 3x

    According to question,

    14x-25.5×14/17+5÷3x-25.5×3/17+2.5 =80/20

    14x-21+5/3x-4.5+2.5 = 4/1

    14x-16x=12x-8

    2x=8

    x=4

    ∴ quantity of mixture in vessel = 17x⇒17×4

    = 68 litre