The distance between two places- A and B is 110 km. 1st car departs from place A to B, at a speed of 40 km/h at 11 a.m., 2nd car departs from place B to A at a speed of 50 km/h at 1 p.m. At what time will both the cars meet each other
Explanation:
distance =110 km
A = 1st car(Speed=40km/h)11a.m
B= 2nd car(Speed=50km/h)1 p.m
Distance travelled by 1st car till 1 p.m
=Speed×Time = 40×2=80km
Remaining distance = 110-80 = 30km
Now, Meeting time = Distance/Relative speed
= 30/50+40 = 30/90
=1/3×60
=20min
Total time = 2 hours 20min
So, at 1.20 p.m. both the cars will meet each other.
