Two mobile phones were purchased at the same price. One was sold at a profit of 20% and second was sold at a price which was INR 1520/- less than the price at which the first was sold. If the overall profit earned by selling both the mobile phones was 1%, what was the cost price of one mobile phone
Let the cost price of one mobile = INR x
According to question,
x×120/100+(x×120/100-1520)=2x×101/100
6x/5+6x/5-1520=202/100x
12x/5-202x/100=1520
38/100x=1520
x=INR4000/-
A jar has 40 litre milk. From the jar, 8 litre of milk was taken out and replaced by an equal quantity of water. If 8 litre of the newly formed mixture is taken out of the jar. What is the final quantity of milk left in the jar
Directions (next 6 questions) : In these questions, two questions numbered I and II are given. You have to solve both the equations and mark the appropriate option.
Give answer :
I. 6x2+11x+3=0
II 20y2+9y+1=0
I. 30x2+17x+2=0
II 3y2+8y+4=0
I. 4x2-13x+10=0
II 2y2-15y+22=0
I. x2-10x+25=0
II y2-9y+20=0